Electrical components can be connected in two ways: either a Series connection or a Parallel connection. Both types of connections have their advantages and use. We will start by looking at the series connection. Use the resistor in the series calculator to accelerate your calculation.

## Series Resistor connection:

Two components will be called in series if the node where they are connected has no other component connected to it.

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Suppose two resistors are connected at point b, and the head of the second resistor is connected to the tail of the first resistor. Resistors commonly have no head and tails. But when current flows, you may assign them head and tails by assigning positive and negative signs based on voltage drop, as shown.

*The Series circuit provides only one path for the current.*

Notice that there is only one path for the current to flow. The positive terminal of R_{2} is connected to the negative terminal of R_{1} and there is no circuit element connected to that point based on the supposition that current is flowing from point a toward point c. If there is any third circuit component (source or resistor) connected to point b, the R_{1} and R_{2} will no longer be in series with each other.

## The Resistor in the Series Calculator:

## The Resistor in the Series Circuit Formula:

Up till now, we have defined and tried to identify the type of circuit. The next step is to learn, how to find equivalent resistance in a complex circuit? Suppose we have the following complex circuit and we are interested to answer the following questions.

#### What is the total current, the source is providing?

To find out the total current source is provided, first, we need to know how much resistance the source experience? The total resistance we can calculate using the following formula or use the resistor in the series calculator. Here “n” is the total number of resistors connected in series, in our case n=3.

$R_{Equivalent}=R_{1}+R_{2}+\ldots +R_{n} $

$R_{Eq}=R_{1}+R_{2}+R_{3}$

Suppose $R_{1} R_{2}$ and $R_{3}$ are 20, 40, and 10 $ \Omega $ respectively. By putting the values in the above formula, we get:

$R_{Eq}=20\Omega +40\Omega +10\Omega $

$R_{Eq}=70\Omega $

After finding the equivalent resistance, the circuit can be reduced to the following circuit and find the total current.

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$I_{T}=\frac{V}{R_{Eq}}$

$=\frac{140 v}{70 \Omega } $

$I_{T}=2 A$

#### What is the current in each resistor?

For all the resistors in a series circuit, there is always only one path for the current to flow. Because of being on the same path, the current is always the same for all series-connected resistors, as the following equation represents.

$I_{T}=I_{1}=I_{2}=\ldots =I_{n} $

Here I_{1}, I_{2,} and I_{n} are the current of R1, R2, and Rn respectively, and n represents the total number of resistors. In our case, the current for R1, R2, and R3 are I1, and I_{2} and I_{3 }are 2 amperes.

I_{T }= 2 A

I_{1 }= 2 A,

I_{2 }= 2 A,

I_{3 }= 2 A

#### What is the voltage across series resistor?

It is effortless, and the ohm law is the best tool for it because we have the resistance and current of each resistor so we can find the corresponding voltage easily.

V_{1 }= I_{1 }R_{1 }= 2 A x 20Ω = 40 volts

V_{2 }= I_{2 }R_{2 }= 2 A x 40Ω = 80 volts

V_{3 }= I_{3 }R_{3 }= 2 A x 10Ω = 20 volts

$V_{T}=V_{1}+V_{2}+V_{3} $

$V_{T}=40 v+80 v+20 v$

$V_{T}=120 v $

Note that the total voltage drop across the circuit is exactly equal to the voltage applied to the circuit. It also satisfies Kirchhoff’s Voltage Law (KVL). The expression for voltage can be generalized like this.

$V_{T}=V_{1}+V_{2}+\ldots +V_{n}$

$V_{T}=I_{1}R_{1}+I_{2}R_{2}+\ldots +I_{n}R_{n}$

The voltage drop in the series connection can easily be calculated by using Voltage Divider Rule.